If x sin a + y sin y then is equal to
WebLearn how to solve product rule of differentiation problems step by step online. Find the derivative using the product rule (d/dx)(y^2sin(x)). Apply the product rule for differentiation: (f\\cdot g)'=f'\\cdot g+f\\cdot g', where f=y^2 and g=\\sin\\left(x\\right). The derivative of the constant function (y^2) is equal to zero. The derivative of the sine of a function is equal … WebKCET 2007: If xx = yy then (dy /dx) is (A) - (x /y) (B) - (y /x) (C) (1+ log x /1+ log y) (D) 1+ log ((x/y)). Check Answer and Solution for above ques
If x sin a + y sin y then is equal to
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Web30 mrt. 2024 · Question 16 (OR 1st question) If y = 𝑥^sin𝑥 +sin〖 (𝑥^𝑥)〗, find 𝑑𝑦/𝑑𝑥 Let u = 𝑥^sin𝑥 , 𝑣=sin〖 (𝑥^𝑥)〗 Thus, y = u + v Differentiating 𝑤.𝑟.𝑡.𝑥 𝑑𝑦/𝑑𝑥 = 𝑑𝑢/𝑑𝑥 + 𝑑𝑣/𝑑𝑥 Calculating derivative of u and v separately Solving 𝒅𝒖/𝒅𝒙 u = 𝑥^sin𝑥 Taking log both sides log𝑢 = log 𝑥^sin𝑥 log𝑢 = sin𝑥 . log 𝑥 Differentiating 𝑤.𝑟.𝑡.𝑥 (𝑑 (log〖𝑢)〗)/𝑑𝑥 = 𝑑/𝑑𝑥 (sin〖𝑥 … Web19 jul. 2024 · x + y = ± ( x − y) + 4 k π which is true with x = 2 k π or y = 2 k π. Hence sin ( x +) sin x + sin y on a grid of step plus all NW-SE diagonals. The case of the division is much less tractable. Share Cite Follow answered …
Web15 apr. 2024 · If y = sin (m sin^–1 x), then (1 – x^2) y2 – xy1 is equal to A. m^2y B. my C. –m^2y D. none of these asked Apr 15, 2024 in Derivatives by Ichha ( 2.7k points) derivatives WebIf sin(x+y)=log(x+y), then: dxdy = Medium Solution Verified by Toppr sin(x+y)=log(x+y) dxd [sin(x+y)]= dxd [log(x+y)] cos(x+y) dxd (x+y)= x+y1 dxd (x+y) cos(x+y)(1+ dxdy)= x+y1 (1+ dxdy) cos(x+y)(1+ dxdy)− x+y1 (1+ dxdy)=0 (1+ dxdy)(cos(x+y)− x+y1)=0 ⇒ 1+ dxdy=0 ∴ dxdy=−1 Solve any question of Continuity and Differentiability with:-
Webif siny=xsin(a+y) then show that dy/dx=sin^2(a+y)/sina Sin y is equal to x sin(a+y) then dy/dx=Welcome ! 😊 Intro :- main gulshan sharma aapke apne hi biha... WebIf sin −1x=y, then A 0≤y≤π B − 2π≤y≤ 2π C 0
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Web29 mrt. 2024 · Transcript. Question 3 If sin𝜃 = x and sin𝜃 = y , then tan𝜃 is (a) 𝑥𝑦 (b) 𝑥/𝑦 (c) 𝑦/𝑥 (d) 1/𝑥𝑦 Given 𝒔𝒊𝒏𝜽 = x And, sec𝜃 = y 1/cosθ = y 𝒄𝒐𝒔𝜽 = 1/𝑦 Now, 𝒕𝒂𝒏𝜽=sinθ/cosθ = 𝑥/ (1/𝑦) = 𝒙𝒚 … mansfield reformatory preservation societyWeb25 apr. 2024 · If siny =xsin(a+y), prove that dy/dx=(sin2(a+y))/sina differential equations class-12 Share It On FacebookTwitterEmail Please log inor registerto add a comment. … koud warm aircoWebsinasin2(a+y) C sin (a +y) D None of these Solution: Given, siny = xsin(a+ y) ⇒ x = sin(a+y)siny On differentiating w.r. to y, we get dydx = dyd [sin(a+y)siny] = sin2(a+y)sin(a+y)cosy−sinycos(a+y) = sin2(a+y)sina ⇒ dxdy = sinasin2(a+y) koud of warm douchenWebSorted by: 17. You don't actually need Calculus to prove it: sin x − sin y = 2 sin x − y 2 cos x + y 2 . The inequality sin x − y 2 < x − y 2 is well known, while cos x + y 2 … mansfield region in victoria\u0027s high countryWeb5 sep. 2024 · If siny=xsin(a+y),then show that dxdy =sinasin2(a+y) . Medium Open in App Updated on : 2024-09-05 Solution Verified by Toppr siny=xsin(a+y) ∴x=sin(a+y)siny Differentiating w.r.t. xwe get, ∴1=sin2(a+y)sin(a+y)cosy−sinycos(a+y) dxdy ∴1=sin2(a+y)sin(a+y−y) dxdy ∴dxdy =sinasin2(a+y) Was this answer helpful? 0 0 … mansfield reformatory mansfield ohioWebsiny=xsin(a+y) ⇒x= sin(a+y)siny. Differentiating with sides w.r.t. y, we get. dydx= sin 2(a+y)cosysin(a+y)−sinycos(a+y) [Quotient Rule] ⇒ dydx= sin 2(a+y)cosy(sinacosy+ cosasiny)−siny(cosacosy−sinasiny) ⇒ dydx= sin 2(a+y)cos 2ysina+ … koudschuim topmatras gold foamWeb1 apr. 2024 · Solution For If x=sin−1(sin10) and y=cos−1(cos10), then y−x is equal to: [Main Online April 9, 2013(S) \& Jan. 09, 2024 (II)] mansfield reformatory prison ohio haunted